Spent some time trying to compress it, … by kchplr

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

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kchplr

function u(t) {

for(c.width^=0,i=3e3;i--;r=i/30,e=S(t*.7)*.02,w=1e3,z=100+S(i*2+r*e)*600,y=S(C(i+t)),Y=y,x.fillRect(w+w*y,r*2.5+400+z*y*.5,8*Y,7*Y));

Feb 26 2017 9:40 AM UTC

}// 133/140

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Spent some time trying to compress it, but forgot to remove the Y=y. Should be 129 bytes instead of 133.

u/sigveseb

if you do z=99.. instead of z=100.. you can get an extra byte!
u/kchplr

aah, indeed thanks!
u/kchplr

Just figured out the last statement in the for loop can also be placed in the loop body to save two more bytes. I'm new to this codegolfing thing...
u/kchplr

Actually, the first statement, not the last..


      u(t) is called 60 times per second.
      t: elapsed time in seconds.
      c: A 1920x1080 canvas.
      x: A 2D context for that canvas.
      S: Math.sin
      C: Math.cos
      T: Math.tan
      R: Generates rgba-strings, ex.: R(255, 255, 255, 0.5)

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