#circlechallenge Monte Carlo Method by DaSpider

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

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DaSpider

function u(t) {

A=Array(s=2e3).fill().map(Math.random)
for(i=s;i--;(a-.5)**2+(b-.27)**2>.05?0:x.fillRect(a*s,b*s,5,5))a=A[i],b=A[s-i]

Apr 21 2020 11:42 PM UTC

}// 117/140

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#circlechallenge Monte Carlo Method

u/DaSpider

Using only good old Pythagoras. This method can be used to estimate π ≈ 4*(number of points in the circle / total number of points) // t?1:d=g=0;A=Array(s=6e3).fill().map(Math.random);for(i=s;i--;(a**2+b**2)**.5<=1?d++:1)a=A[i],b=A[s-i];g+=s;throw(4*d/g)


      u(t) is called 60 times per second.
      t: elapsed time in seconds.
      c: A 1920x1080 canvas.
      x: A 2D context for that canvas.
      S: Math.sin
      C: Math.cos
      T: Math.tan
      R: Generates rgba-strings, ex.: R(255, 255, 255, 0.5)

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