Infinite Sunset by pbjer

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

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pbjer

function u(t) {

c.width=1920
w=1920
m=255
z=S(t)
x.fillStyle=R(m,100,z*m)
x.fillRect(0,0,w,w)
x.arc(w/2,z*300+800,200,0,6)
x.fillStyle=R(m,m,0)
x.fill()

Mar 1 2021 8:02 PM UTC

}// 136/140

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Infinite Sunset

Show more comments…
u/magna

Neat! Here, I've shaved some bytes to illustrate a few quick wins (also, use 7 instead of 6 for 2π): c.width=w=1920;z=S(t);x.fillStyle=R(m=255,99,z*m);x.fillRect(0,0,w,w);x.arc(w/2,z*300+800,200,0,7);x.fillStyle=R(m,m);x.fill()
u/danny@hille.dk

wrap it in with(x) is also a quickwin if you have more than 3 canvas operations
u/danny@hille.dk

c.width=w=1920;z=S(t);with(x)fillStyle=R(m=255,99,z*m),fillRect(0,0,w,w),arc(w/2,z*300+800,200,0,7),fillStyle=R(m,m),fill()
u/danny@hille.dk

z=S(t) takes up more space than having S(t) inline
u/danny@hille.dk

if you are willing to make some compromises, you can use your constant m to replace values close to 255
u/danny@hille.dk

and use 2e3 instead of 1920
u/danny@hille.dk

117 b => c.width=w=2e3;with(x)fillStyle=R(m=255,99,S(t)*m),fillRect(0,0,w,w),arc(w/2,S(t)*m+800,m,0,7),fillStyle=R(m,m),fill()
u/danny@hille.dk

113 => w=c.width|=0;with(x)fillStyle=R(m=255,99,z=S(t)*m),fillRect(0,0,w,w),fillStyle=R(m,m),arc(w/2,z+800,m,0,7),fill()


      u(t) is called 60 times per second.
      t: elapsed time in seconds.
      c: A 1920x1080 canvas.
      x: A 2D context for that canvas.
      S: Math.sin
      C: Math.cos
      T: Math.tan
      R: Generates rgba-strings, ex.: R(255, 255, 255, 0.5)

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