Works best in full screen, otherwise li… by eruonna

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

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eruonna

function u(t) {

a=[0,9,0,-9,0]
if(t){if(i>=0){d=(p[i--]+1)%4;p.push(d);j++;b+=a[d];c-=a[d+1];x.lineTo(b,c);x.stroke()}else i=j}else{p=[0];i=j=0;b=960;c=540}

Apr 17 2017 8:56 PM UTC

}// 140/140

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Works best in full screen, otherwise line is too thin

u/donbright

how does it work ?
u/eruonna

One way to draw the next iteration of the dragon curve is to take the previous iteration and then add it to itself backwards and rotated 90 degrees. Here p is the array of previous steps, j the index of the current step, and i walks backward through p. When i gets to the beginning, we set it equal to j and start over.
u/donbright

thanks, that is fascinating


      u(t) is called 60 times per second.
      t: elapsed time in seconds.
      c: A 1920x1080 canvas.
      x: A 2D context for that canvas.
      S: Math.sin
      C: Math.cos
      T: Math.tan
      R: Generates rgba-strings, ex.: R(255, 255, 255, 0.5)

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