rotating square by Ghoust

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

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Ghoust

function u(t) {

f=[c.width=99]
for(i=4;i--;){f[i*2]=S(d=t+i*1.5)*9;f[i*2+1]=C(d)*9}for(i=8;i--;)f[i]+=i<2?30:-f[i-2]
x.stroke(p=new Path2D('m'+f))
x.fill(p)

Sep 19 2022 12:01 PM UTC

}// 140/140

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rotating square

u/Ghoust

does anyone know a better way of doing this?
u/danny@hille.dk

I'm not sure it's better, but this another way: c.width+=0; x.translate(960,540); x.rotate(t); x.fillRect(-250,-250,500,500)
u/KilledByAPixel

for(c.width|=i=4;i--;x.fill())x.arc(960,540,500,a=i*11+t,a)
u/rodrigo.siqueira

I like this 3D rotation: x.fillRect(700,300,400,400) ; c.style="transform:rotate3d(1,5,2,"+t*2+"rad)"


      u(t) is called 60 times per second.
      t: elapsed time in seconds.
      c: A 1920x1080 canvas.
      x: A 2D context for that canvas.
      S: Math.sin
      C: Math.cos
      T: Math.tan
      R: Generates rgba-strings, ex.: R(255, 255, 255, 0.5)

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