A very reliable and non-laggy method to… by deobfuscate

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

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deobfuscate

function u(t) {

c.width+=0
x.font='5em"'
for(i=1e3;i--;)x.fillText(`${i>1?'else ':''}if(number==${i})return ${i%2==0?'true':'false'};`,100,100*i+t*-200+500)

Sep 26 2023 2:21 PM UTC

}// 140/140

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A very reliable and non-laggy method to check for even numbers.

Show more comments…
u/cantelope

is 1.5 even or odd?
u/tomxor

Technically: neither, because it's not a natural number. Practically: depends on rounding method, likely even. For fun: if you ignore the exponent then it's odd i.e 1.5=15=odd
u/Joachim

Lost 10 chars —> x.font='5em"' for(c.width=i=1e3;i--;)x.fillText(${i?'else ':''}if(number==${i})return ${i%2?'false':'true'};,99,99*i+t*-200+500)
u/Joachim

report Lost 10 chars —> x.font='5em"' for(c.width=i=1e3;i--;)x.fillText(${i?'else ':''}if(number==${i})return ${i%2?'false':'true'};,99,99*i+t*-200+500)
u/Joachim

Ah well. You’ve basically just got to add the backslashes back in for it to work.
u/deobfuscate

119 chars, add ticks for(i=c.width=1e3;i--;x.font='3em"')x.fillText(${i?'else ':''}if(number==${i})return ${i%2==0};,100,100*i+t*-200+500)


      u(t) is called 60 times per second.
      t: elapsed time in seconds.
      c: A 1920x1080 canvas.
      x: A 2D context for that canvas.
      S: Math.sin
      C: Math.cos
      T: Math.tan
      R: Generates rgba-strings, ex.: R(255, 255, 255, 0.5)

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