A 2 color plasma, couldnt fit the 3:d c… by New_Core

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

Please log in (or register) to post a dweet (copy-paste the code somewhere safe to save it meanwhile)


    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

show FPS hide FPS share 1 remix fullscreen

New_Core

function u(t) {

a=c.width=100;d=x.getImageData(0,0,a,a);p=d.data;for(i=3e4;i-=4;)b=a*S(i/5e3+t),q=i%400,p[i]=b+q,p[i+1]=-b+q,p[i+3]=i;x.putImageData(d,0,0);

Aug 24 2016 3:40 PM UTC

}// 140/140

Please log in (or register) to post as a new dweet (copy-paste code somewhere safe to save it meanwhile).

A 2 color plasma, couldnt fit the 3:d color

u/icecuber

Can you fit the 3:d color with this (reduced 21 bytes)? a=c.width=99;d=x.getImageData(0,0,a,a);for(i=3e4;i--;)d.data[i]=i%396+[b=S(i/5e3+t),-b,,i][i%4]*a;x.putImageData(d,0,0)
u/New_Core

nice.. that is much better
u/New_Core

a 3 color test added on icecubers code a=c.width=99;d=x.getImageData(0,0,a,a);for(i=3e4;i--;)d.data[i]=i%396+[S(q=i/5e3+t)*0.6,S(q+t)*0.3,S(q+t*4),i][i%4]*a;x.putImageData(d,0,0)
u/iverjo

Nice :) I find your attempt at plasma better than mine: Btw, you can replace 0.6 with .6 and similarly for 0.3
u/iverjo

https://dwitter.net/d/48


      u(t) is called 60 times per second.
      t: elapsed time in seconds.
      c: A 1920x1080 canvas.
      x: A 2D context for that canvas.
      S: Math.sin
      C: Math.cos
      T: Math.tan
      R: Generates rgba-strings, ex.: R(255, 255, 255, 0.5)

dwitter.net