d/5271 by RomanW

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

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RomanW

remix of d/5233 by u/RomanW

function u(t) {

z=34;f=(60*t)%960;'ȏ܀လa8๼0৷耠ĻƟ臿ﰿ聛＝〇ﾛ态繨ﰀε＀Əﾀ؇￠ᨃ￠簁｠㼀＀羀羀翀⟀῀㏠࿀ᇰϠᡰǰ࠸xࠌ࠘ం耄᠀〆㠀ข瀡Ǡ耿'.charCodeAt(f/16)>>f%16&1&&x.fillRect(f%31*z,~~(f/31)*z,z,z)

Jan 2 2018 4:12 PM UTC

}// 140/140

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Show more comments…
u/Pjaerr

That's cool.
u/Chipnstein

Was expecting dickbut... not exactly disappointed but still cool
u/aemkei

OMFG! This is incredible!!
u/aemkei

but shorter but ugly: f=60*t;x.fillRect(f%31*9,f/3,'ȏ܀လa8๼0৷耠ĻƟ臿ﰿ聛＝〇ﾛ态繨ﰀε＀Əﾀ؇￠ᨃ￠簁｠㼀＀羀羀翀⟀῀㏠࿀ᇰϠᡰǰ࠸xࠌ࠘ం耄᠀〆㠀ข瀡Ǡ耿'.charCodeAt(f/16)>>f%16&1,9)
u/RomanW

Nice aemkei, thanks!
u/oldspork

This is amazing. I'm brand-new to coding and very new to Dwitter; how on Earth do all of those symbols and letters code for a picture of the Earth?
u/RomanW

Hi oldspork! The magic happens with the function charCodeAt. This function gets the numeric value of one character at a time. Since these are UTF-16 characters, you can get 16 bits of information in one character.
u/lionleaf

#globe #earth #bitmap #pixelart
u/Purpzie

Is there an easy way to make these kinds of things? (specifically how the data for each pixel is stored)
u/dsamarin

String.fromCharCode.apply(null, new Uint16Array(34).map((r) => Math.random()*0xffff))


      u(t) is called 60 times per second.
      t: elapsed time in seconds.
      c: A 1920x1080 canvas.
      x: A 2D context for that canvas.
      S: Math.sin
      C: Math.cos
      T: Math.tan
      R: Generates rgba-strings, ex.: R(255, 255, 255, 0.5)

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