Hello guys. I need ideas on how can i o… by lowpoly

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

Please log in (or register) to post a dweet (copy-paste the code somewhere safe to save it meanwhile)


    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

show FPS hide FPS share fullscreen

lowpoly

function u(t) {

for(o=10;o--;)with(c){if(!t){i=j=k=l=1;w=width=399;h=height=101;}k*=(i<=0||i>=w)?-1:1;l*=(j<=0||j>=h)?-1:1;x.fillRect(i+=k,j+=l,1,1)}

Jan 4 2018 12:47 AM UTC

}// 133/140

Please log in (or register) to post as a new dweet (copy-paste code somewhere safe to save it meanwhile).

Hello guys. I need ideas on how can i optimize this thingie :)

u/lowpoly

and yea, the k*=(i<=0||i>=w)?-1:1; l*=(j<=0||j>=h)?-1:1; part concerns me most
u/joeytwiddle

Well this is 2 chars shorter: if(j<=0||j>=h)l=-l; // and this is the same: (j<0||j>h)&&(l=-l); // You could also drop the four =s for a small loss in quality.
u/sigveseb

Looks nice!


      u(t) is called 60 times per second.
      t: elapsed time in seconds.
      c: A 1920x1080 canvas.
      x: A 2D context for that canvas.
      S: Math.sin
      C: Math.cos
      T: Math.tan
      R: Generates rgba-strings, ex.: R(255, 255, 255, 0.5)

dwitter.net