141/140 I broke the matrix by Galaxtone

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

Please log in (or register) to post a dweet (copy-paste the code somewhere safe to save it meanwhile)


    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

show FPS hide FPS share fullscreen

Galaxtone

function u(t) {

for(i=0;i<10;i++){x.fillStyle=R(S(t)*255,C(t)*255);x.beginPath();
x.ellipse(400+i*99+S(t)*300,S(t)*99+400,50,C(t)*99+200,0,0,3,1);x.fill();}

Apr 16 2018 12:39 AM UTC

}// 140/140

Please log in (or register) to post as a new dweet (copy-paste code somewhere safe to save it meanwhile).

141/140 I broke the matrix

u/prplz

When the order of your for loop isn't important you can make it count backwards like this for(i=10;i--;)
u/Galaxtone

oh nice thx for the tip I'm new to this code-golfing site
u/Galaxtone

also I saw something about using with(x) so I think I'll use that for future stuff :p
u/Galaxtone

for(i=10;i--;)with(x){fillStyle=R(S(t)*255,C(t)*255);beginPath(); ellipse(400+i*99+S(t)*300,S(t)*99+400,50,C(t)*99+200,0,0,3,1);fill()} Saved 5 whole bytes using that


      u(t) is called 60 times per second.
      t: elapsed time in seconds.
      c: A 1920x1080 canvas.
      x: A 2D context for that canvas.
      S: Math.sin
      C: Math.cos
      T: Math.tan
      R: Generates rgba-strings, ex.: R(255, 255, 255, 0.5)

dwitter.net