Cannot compress it, help me by Barth

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

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Barth

function u(t) {

for(a=990,c.width=1920,x.font="99px a",i=0;i<20;i++)x.lineTo(99*i,9*S(i-t)+a);x.fill(),x.translate(a,a),x.rotate(C(t)/5),x.fillText("🚴",0,0)

May 22 2018 6:00 AM UTC

}// 140/140

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Cannot compress it, help me

u/prplz

Try c.width|=0. This uses the "bitwise or" operator on the width, which does nothing with zero. Any time width is written to, the canvas is cleared
u/Barth

Thanks
u/Barth

https://www.dwitter.net/d/8195
u/jellyedwards

with(x){...} saves on every x. : with(x){for(a=990,c.width=1920,font="99px a",i=0;i<20;i++)lineTo(99*i,9*S(i-t)+a);fill(),translate(a,a),rotate(C(t)/5),fillText("🚴",0,0)}
u/jellyedwards

he follows the hills a bit better here: with(x){for(a=990,c.width|=0,font="99px a",i=0;i<20;i++)lineTo(100*i,99*C(i-t)+a);fill(),translate(a,a),rotate(C(t)/3),fillText("🚴",200,0)}


      u(t) is called 60 times per second.
      t: elapsed time in seconds.
      c: A 1920x1080 canvas.
      x: A 2D context for that canvas.
      S: Math.sin
      C: Math.cos
      T: Math.tan
      R: Generates rgba-strings, ex.: R(255, 255, 255, 0.5)

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