I'm working on a version with green mou… by keithclark

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

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keithclark

function u(t) {

for(c.width=240,Z=5;Z>0;Z-=.1)for(Y=X=-60;X<60;x.fillRect(120+X++/Z*9,45-Y/Z,1/Z*24-Z,99))I=C(X*.4^Z+t*6),Y+=7*I,x.fillStyle=R(Z*50-Y*I/3)

Jul 3 2018 4:27 PM UTC

}// 138/140

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I'm working on a version with green mountains and water but I need to shave a few bytes of this one first. Suggestions welcome

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u/alien

wow very nice
u/alien

is this what they call raymarching?
u/aleamb

yeeeeeeeeeeeeeeeeeeahh awesomeee!
u/aleamb

#3d #landscape #awesome
u/Agnes

Both 240, 120 and 60 are multiples of 60 so I think you can lose bytes by making 60 a constant... somehow. Right?
u/keithclark

@alien - no raymarching here. This is a cos() generated waveform, drawn from back to front.


      u(t) is called 60 times per second.
      t: elapsed time in seconds.
      c: A 1920x1080 canvas.
      x: A 2D context for that canvas.
      S: Math.sin
      C: Math.cos
      T: Math.tan
      R: Generates rgba-strings, ex.: R(255, 255, 255, 0.5)

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