Dweets awesomed by u/Quant1um

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

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Current theme challenge: #Opposites

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yonatan

function u(t) {

eval(unescape(escape`景爨椽ㄲ〰㭩ⴭ㭸⹣汥慲剥捴⡺ⱺⰸⰸ⤩樽椾㸱ⱸ孳㴧獥瑔牡湳景牭❝⠱㘬〬〬㠬堽樥ㄶ⨱㈸⬨樦ㄶ㼰㨶㐩ⱙ㴱ㄳ㈭⡩☭㌲⤫䌨横⨳⭴⨳⤪⨴⨹㤪匨琩⨪㐩ⱸ⹦楬汒散琨稽ⴴⱺⰸⰱ攳⤬硛獝⠸ⰴⰭ㠬㐬堬夭㌲⤻`.replace(/u(..)/g,"$1%")))

Nov 6 2018 9:55 PM UTC

}// 140/140

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for(i=1200;i--;x.clearRect(z,z,8,8))j=i>>1,x[s='setTransform'](16,0,0,8,X=j%16*128+(j&16?0:64),Y=1132-(i&-32)+C(j**3+t*3)**4*99*S(t)**4),x.fillRect(z=-4,z,8,1e3),x[s](8,4,-8,4,X,Y-32);

u/yonatan

I think there was something like this by #beesandbombs (but with perspective, and maybe triangles?)
u/katkip

nice one\
u/twitter

for(h=i=1200;i--;x.clearRect(z,z,8,8))j=i>>1,x[s='setTransform'](16,0,0,8,X=j%16*128+(j&16?0:64),Y=h-(i&-32)+C(j**3+t*3)*99*S(t)**4),x.fillRect(z=-4,z,8,h),x[s](8,4,-8,4,X,Y-32) - 177

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yonatan

remix of d/10837 by u/veubeke

function u(t) {

c.width=i=w=300
x.font='6em"',
x.fillText('Shadow',S(t)*99,m=99)
for(i;i--;x.fillRect(0,i,w,i/w))x.drawImage(c,0,m-i,w,1,-i*4,m+i,w+i*8,.2)

Nov 5 2018 4:01 PM UTC

}// 139/140

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u/iverjo

Wow! Nice #shadow technique

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f8f82804

remix of d/10809 by u/f8f82804

function u(t) {

c.width=480;for(k=8;k--;)for(n=7;n--;x.lineTo(240+400*r*C(p)/z,160*'0347430'[n]/z))r=n%3>0,z=5+r*S(p=n%4/1.6+1.26*k-t%1.26+3.14);x.stroke()

Nov 1 2018 6:03 PM UTC

}// 139/140

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#wireframe #d3 #perspective #decahedron #d10 -- tweaked the geometry slightly and added weight to some lines by drawing them multiple times with a small angular error

u/f8f82804

#pentagonal #trapezohedron

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jylikangas

remix of d/7979 by u/jylikangas

function u(t) {

eval(unescape(escape`睩瑨⡸⥦潲⡣⹷楤瑨㵩㴭㔻⬫椼㔻䌽愽㹬楮敔漨⡘㵓⡴⤪㤩⬱㔰⭡⨵㤯⡺㵪⵴┱⤬㠰⬨吽㤹⭓⡪⭴♡⤪㌰⤯稭堪㈩⥦潲⡪㴷㭢敧楮偡瑨⡦楬氨⤩ⱃ⡩⤬ⴭ樻䌨椫ㄩⱪ⬫ⱃ⡩⬱⤬樭⴩晩汬却祬攽刨䌨椩ⱔ⼲⭪⨲〩`.replace(/u(..)/g,"$1%")))

Oct 29 2018 4:08 PM UTC

}// 140/140

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3D landscape with compressor's help

Show more comments…
u/lionleaf

#landscape
u/sigveseb

Niiiice
u/rbong

Incredible!
u/joeytwiddle

Reminds me of Zarch (1987)
u/f8f82804

#d3 #wireframe #perspective #shading
u/katkip

cool

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pavel

function u(t) {

g=_=>2*Math.random()-1;Y=g(X=g(r=512));h=X*X+Y*Y<=1
x.fillStyle=R(a=99+!h*99,a,a);x.fillRect(r+r*X,r+r*Y,32,32)
t?0:n=d=0;throw 4*(n+=h)/++d

Oct 27 2018 3:13 AM UTC

}// 140/140

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Estimating Pi using the Monte Carlo Method

u/katkip

Genius!
u/pavel

#pi

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yonatan

function u(t) {

c.style.background=`linear-gradient(#357, #f023 50%,#8428 50%,#434),radial-gradient(circle at center,#fff 7%,#fd8 9%,#ca8 33%)`

Oct 26 2018 9:16 PM UTC

}// 127/140

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#sunset

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New_Core

remix of d/10639 by u/yonatan

function u(t) {

s=c.style;s.backgroundBlendMode='overlay';for(b=[i=5];i--;s.background=b)b[i]=`repeating-radial-gradient(${S(t+i)+3}%${i}%,#ffd,#012 999%)`

Oct 26 2018 5:41 PM UTC

}// 139/140

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joeytwiddle

function u(t) {

c.width|=k=300,x.font='20em"',b=t*60%19683
for(i=9;i--;x.fillText(" ⚬×"[v],580+k*(i%3),380+k*(i/3|0)))
v=(b/3**i|0)%3

Oct 26 2018 5:24 AM UTC

}// 117/140

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Every possible tic-tac-toe board (and some impossible too)

u/joeytwiddle

Challenge: Every possible tic-tac-toe game (no illegal boards)
u/pavel

Here, but only problem is that it keeps playing after winning: c.width|=k=300,x.font='20em"',b=frame>>4,m=b&1 for(i=9;i--;)x.fillText("⚬× "[b&2<<i?m^=1:2],580+i%3*k,380+k*(i/3|0))
u/pavel

Oh, nevermind. Its missing boards because it doesn't permute X and O fully for each template.
u/joeytwiddle

Good effort anyway!

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rodrigo.siqueira

function u(t) {

c.width=600;
for(n=1;n<9;n++) {
 for(i=1;i<8;i=i+6.28/n) {
  x.lineTo(S(t)*C(i)*35+370+n*80-450,200+S(i)*80)
 }
 x.stroke()
}

Oct 25 2018 10:00 PM UTC

}// 126/140

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Polygon showcase

u/f8f82804

I love the 2-gon!

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f8f82804

remix of d/10658 by u/f8f82804

function u(t) {

for(c.width|=i=13;i--;x.lineTo(967+(y-1?0:1e3*S(p)/z),1e3*y/z))y='011112101211'[i],z=y-1?3:3+C(p=t+1.57*'012340302014'[i]);x.fill('evenodd')

Oct 25 2018 5:41 PM UTC

}// 140/140

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#d3 #perspective #octahedron

u/pavel

Here is 12 characters saved: c.width^=i=0;for(y of'111121012110')x.lineTo(960+y%2*S(p=t+1.6*'123403020140'[i++])*(z=1600/(3+y%2*C(p))),y*z);x.fill('evenodd')
u/f8f82804

using 1.6 to approximate Math.PI/2 is OK, but you should change all the 4s to 0s in the second data string, just to minimze the aggregate angular error. I used 4 for clarity, because 1.57 is accurate enough that the error is hard to notice. With 1.6 you can notice that one edge is longer than the others. c.width^=i=0;for(y of'111121012110')x.lineTo(960+y%2*S(p=t+1.6*'123003020100'[i++])*(z=1600/(3+y%2*C(p))),y*z);x.fill('evenodd')

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