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function u(t) {
} //
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u(t) is called 60 times per second. t: Elapsed time in seconds. S: Shorthand for Math.sin. C: Shorthand for Math.cos. T: Shorthand for Math.tan. R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5) c: A 1920x1080 canvas. x: A 2D context for that canvas.
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remix of d/10800 by u/Xen

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  • #pentagram -- technically a pentagrammic star dipyramid

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  • u/f8f82804
    making this work as intended in the size limit will require coming up with a more clever way of iterating over the vertices, either via a formula or a more clever encoding of their coordinates

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remix of d/10688 by u/yonatan

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  • 【filterworld】

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  • u/pavel
    Here is 12 characters saved: c.width^=i=0;for(y of'111121012110')x.lineTo(960+y%2*S(p=t+1.6*'123403020140'[i++])*(z=1600/(3+y%2*C(p))),y*z);x.fill('evenodd')
  • u/f8f82804
    using 1.6 to approximate Math.PI/2 is OK, but you should change all the 4s to 0s in the second data string, just to minimze the aggregate angular error. I used 4 for clarity, because 1.57 is accurate enough that the error is hard to notice. With 1.6 you can notice that one edge is longer than the others. c.width^=i=0;for(y of'111121012110')x.lineTo(960+y%2*S(p=t+1.6*'123003020100'[i++])*(z=1600/(3+y%2*C(p))),y*z);x.fill('evenodd')

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