Hot dweets by u/mxfh

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

Try the new frontend: beta.dwitter.net
Current theme challenge: #Opposites

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mxfh

remix of d/2442 by u/mxfh

function u(t) {

c.width|=b=50
h=b-S(t)*b*5
for(e=6.28;e>0;x.lineTo(d*C(e-=~~(h%e)?.01:1/e)+h*C(s=d/b*e)+960,(d)*S(e)-h*S(s)+540))d=300-b
x.fill("evenodd")

Aug 29 2024 12:50 AM UTC

}// 138/140

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#opposites #Bouba #Kiki

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mxfh

remix of d/32247 by u/rodrigo.siqueira

function u(t) {

c.width|=h=C(t)
with(x)for(h,transform(X=~~(9+h*9),h,C(167/h),X,960,600);X--;fill(new Path2D(`M${T(h+X)-9} 9 h25 l-3-5 h-19`)))rotate(2.094)

Aug 14 2024 11:24 PM UTC

}// 140/140

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u/rodrigo.siqueira

It is possible to save 2 characters by changing the beginning of the code this way: with(x)for(reset(h=C(t)),h,... I found that x.reset() is the same as c.width|=0 but shorter. So, I usually don't use c.width|=0 trick anymore. And you can add code inside parentheses so you don't need the "enter" or ";" characters. E.g. : x.reset(code here)

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mxfh

remix of d/2414 by u/mxfh

function u(t) {

with(x)for(transform(X=19,0,0,X,960,540),fillText('CORPORATE',-30,X);X-->9;fill(new Path2D(`M-9 9 h25 l-3-5 h-19.2`)))rotate(2.094)

Aug 13 2024 8:43 PM UTC

}// 131/140

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#Logo #transform

u/KilledByAPixel

nice! it's a good show, i give it my official recommendation.
u/tem

I find the way to render for so long

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mxfh

remix of d/27322 by u/rodrigo.siqueira

function u(t) {

c.style.filter=`invert(`
for(ⵠ=1e4;ⵠ--;ƒ(0,0,300,ⵠ))ƒ=(β,α,ထ,ට)=>ထ>1?ƒ(α+ထ*C(ට),β+ထ*S(ට),ထ/3,T(ට/99+t*ට)):x.fillRect(β+t<<ⵠ,α+510,.1,T(t+ⵠ))

Apr 19 2023 12:45 AM UTC

}// 140/140

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accidental cloud chamber

u/deobfuscate

Did you HAVE to use stuff like ⵠ as variables?
u/deobfuscate

nvm, saw the original
u/Xen

nice!
u/mxfh

Yes I do anyway. What’s not to like about it? See https://www.dwitter.net/d/855 anyway. Find it most descriptive in the context of the limitations of dwitter. Btw this just done fudging and pasting around in iOS Safari when I can’t fall asleep. Just did feel like posting this one.

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mxfh

function u(t) {

for(c.width|=i=2e3;i--;x.fillRect(i%99*20+S(t)*t*3,i/30*20+C(t)*t*3-99,20,t*8))x.fillStyle=R(99+S(t)*i%255,99+C(t)*i%255,T(i/99)*255+i%2*50)

Apr 4 2023 3:52 PM UTC

}// 140/140

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first attempt at #GPT-4 assisted mashup of my dweets imported from a dump from https://dweetabase.3d2k.com/

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mxfh

remix of d/23558 by u/mxfh

function u(t) {

this.b||(I=new ImageData(w=2048,w),b=new Int32Array(I.data.buffer))
for(i=3e6;i--;b[i]=b[i-w]-(i-Y&Y+i)*t)Y=i*w
x.putImageData(I,0,0)

Aug 17 2022 11:41 PM UTC

}// 133/140

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new weird mountain ranges

u/mxfh

mostly this (lol) just answers my own question, if the buffer can be reused in source of this remix.
u/magna

Keeps on giving

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mxfh

remix of d/23817 by u/pavel

function u(t) {

for(i=420;r=--i>>1;i&2||x.beginPath(x.fill()))x.fillStyle=`hsl(177,42%,${90-3*r}%`,x.arc(960,580,20*r,a=(i*9+(~r%2)*C(t-r/9))/.9549,a)

Oct 7 2021 4:38 PM UTC

}// 134/140

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Looks like iOS safari closes arc in a weird way. Adding some offset to the end fixes this: … a+0.001)

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mxfh

remix of d/24011 by u/KilledByAPixel

function u(t) {

for(w=710,r=113,τ=w/r,c.width|=i=0;i<w;i+=τ/3+S(t)/20)x.arc(w,w,i**(-.7+T(t)/9)*1e4,a=i+t,a+τ/4)
x.stroke()

Oct 7 2021 4:10 PM UTC

}// 107/140

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#tunnel #cavern

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mxfh

remix of d/24028 by u/mxfh

function u(t) {

for(w=710,r=113,τ=w/r,c.width|=i=0;i<2e4;i+=τ/2+S(t/7)/20)x.arc(w,w,i**(-.7+T(t/5)/9)*1e4,a=i+t,a+τ/16)
x.stroke()

Oct 7 2021 4:17 PM UTC

}// 114/140

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those fractions of τ is a space to explore

u/Chippackage

I love Bézier Animations like this.

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mxfh

remix of d/23536 by u/mxfh

function u(t) {

r=113;c.width|=w=710;for(λ=φ=a=w/r;λ+=a,φ>-a;φ-=.2+S(t/4+φ)/r)x.arc(C(φ)*S(d=λ-t)*r+w,(S(φ+a/4)*C(φ)*C(d))*r+w,φ**4,0,a)
x.fill("evenodd")

Aug 26 2021 8:50 PM UTC

}// 138/140

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slither

dwitter.net | mxfh (1244)