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function u(t) {
} //
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u(t) is called 60 times per second. t: Elapsed time in seconds. S: Shorthand for Math.sin. C: Shorthand for Math.cos. T: Shorthand for Math.tan. R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5) c: A 1920x1080 canvas. x: A 2D context for that canvas.
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remix of d/11016 by u/pavel

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  • Ouroboros

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remix of d/10979 by u/cantelope

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function u(t) {

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  • u/yonatan
    arc?!
  • u/anotherkitten
    oh you sly dog very well done
  • u/pavel
    :)
  • u/jylikangas
    Very cool! You can save 3 bytes by removing the unnecessary %1 from t when calculating a and also doing <<7 instead of *128. If someone is wondering how this works using a+1 instead of a at the end may help. :)
  • u/katkip
    #beesandbombs
  • u/pavel
    Removing %1 at the end breaks the animation on my iPhone.

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  • Demon

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  • This really wants to be faster but I'm out of bytes!
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  • u/jylikangas
    Full speed 138: p=i=>99*[0,0,3-i,1,6-i,2,i-5,i-7][~~i] for(c.width|=i=8,x.rotate(7);i--;m+7&7&&x.fillRect(p(m?i:T=t*5%8)+700,p(m?6-i&7:8-T),90,90))m=~~T-i
  • u/pavel
    Nice! There is some flicker but you saved enough bytes to fix p=i=>99*[0,0,3-i,1,6-i,2,i-5,i-7][~~i];for(c.width|=i=8,x.rotate(7),T=8*t%8;i--;m+7&7&&x.fillRect(p(m?i:T)+450,p(m?6-i&7:8-T),90,90))m=~~T-i
  • u/jylikangas
    This was fun. I also tried two totally different implementations but it seems your approach is the best.
  • u/katkip
    Haha that's fun

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function u(t) {

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  • faster and cleaner version of linear ripple

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function u(t) {

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  • Fibonacci spiral
  • u/katkip
    Owwww woottt thats awesome
  • u/rodrigo.siqueira
    SOURCE CODE: for(c.width|=i=9;i--;x.transform(k=.62*C(a=S(t)*1.57),s=.62*S(a),-s,k,w,w))x.rect(1,1,x.lineWidth=w=300,w),x.quadraticCurveTo((z=150)+S(t)*z,z-S(t)*z,w,w);x.stroke();
  • u/rodrigo.siqueira
    Animated Golden Rectangle #Fibonacci Sequence
  • u/vain
    very cool golden ratio / rectangle fx. (never seen before like this, great!)

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  • for(c.width|=i=512;i--;x.fillRect(960+p.x*p.w,540+p.y*p.w,p.w,p.w))p=new DOMMatrix([...'3000030000350000']).rotateAxisAngle(t,t,0,t*99).transformPoint(new DOMPoint(i>>6&7,i>>3&7,i&7));

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