Top dweets by u/pavel

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

Try the new frontend: beta.dwitter.net
Current theme challenge: #Opposites

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pavel

remix of d/9409 by u/trupples

function u(t) {

r=n=>q>3&&T(i*n)%2*(q-3)*300
for(c.width|=i=200,x.font='9em"';--i;x.fillText('Awesome!'[i&7],2e3-r(7)-q*300,1e3-(6-q)*q*90+r(3)))q=2*t++%16

Nov 18 2018 6:27 AM UTC

}// 139/140

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Awesome #fireworks

u/magna

Awesome indeed! #awesomebait

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pavel

remix of d/10922 by u/pavel

function u(t) {

with(x)for(c.width=960,s=270;s>2;stroke())rect(0,0,s*=.618,s),quadraticCurveTo(X=s*(.5+S(t)*.45),s-X,s,s),translate(s,s),rotate(T=S(t)*1.57)

Nov 10 2018 2:33 AM UTC

}// 140/140

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u/jonathan-potter

This is great! I spent some more time trying to use x.scale for sizing to make the math super pretty. It just ended up messier because linewidth needed modification :(

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pavel

remix of d/10875 by u/pavel

function u(t) {

x.rotate(!t*Math.PI/4);for(i=24;i--;)for(j=28;j--;x.fillRect(i*99+d-250,j*99-2e3+d,99,99))x.fillStyle=R(a=(i+j)%2*256,a,a),d=T(i*j/99+t/9-1)

Nov 7 2018 1:08 AM UTC

}// 140/140

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Rain

u/katkip

What rain lol

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pavel

function u(t) {

g=_=>2*Math.random()-1;Y=g(X=g(r=512));h=X*X+Y*Y<=1
x.fillStyle=R(a=99+!h*99,a,a);x.fillRect(r+r*X,r+r*Y,32,32)
t?0:n=d=0;throw 4*(n+=h)/++d

Oct 27 2018 3:13 AM UTC

}// 140/140

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Estimating Pi using the Monte Carlo Method

u/katkip

Genius!
u/pavel

#pi

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pavel

remix of d/10601 by u/anotherkitten

function u(t) {

with(x)for(i=60;r=5e-9*(i+3*t%2)**6,d=S(r/25-4*t)*r,--i;beginPath(fill(arc(960+d,540+d,9*r,0,7))))fillStyle=`hsl(${r+i%2*r-20*t} 50%${r/2}%`

Oct 23 2018 1:56 AM UTC

}// 140/140

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u/iverjo

#tunnel

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pavel

function u(t) {

w=c.width=500
for(i=98;i--;)for(j=55;X=i/9-5,Y=j/9-3,Z=3*S(t),j--;)(X**3+Y**3+Z**3-2*C(t)*X*X*Y*Y)<9&&x.fillRect(5*i,5*j,5,5)

Oct 15 2018 4:40 AM UTC

}// 125/140

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pavel

remix of d/20353 by u/solendil

function u(t) {

d=(V,D,i=1<<V/8%16)=>x.fillRect(X,Y,X+Y+D&2,1,x.fillStyle=R((4591&i)*w,(4096&i)*w));for(X=t?0:c.width=w=512;X--;)for(Y=288;Y--;d(X,0))d(Y,2)

Oct 22 2020 9:59 PM UTC

}// 140/140

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4591 and 4096 specify the 16 bit patterns for the red / green channels

u/pavel

0001000111101111 and 0001000000000000 respectively (rendering flips the order)
u/danny@hille.dk

👍
u/solendil

Congratulations ! :)
u/tomxor

nice

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pavel

function u(t) {

f=(i,j=i%1,k=~~i,m=j*j*(3-2*j))=>S(k*k)*m---m*S(--k*k)
for(i=c.width|=0;i--;)x.fillRect(i,540+99*f(i/32+5*t),5,5)

Mar 28 2020 9:41 PM UTC

}// 113/140

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I would love to find a better / shorter 1D noise function #challenge

u/pavel

This one assigns a 'random' number to each integer k via S(k*k) and uses smoothstep to interpolate between them.
u/pavel

Another idea to play around with f=(i,n=9)=>n&&C(n**.5*i)/n+f(i,n-1)
u/joeytwiddle

#random

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pavel

function u(t) {

for(c.width=640,i=8;i--;x.stroke())x.beginPath(r=150*2/3*(i>1)),x.arc(320+r*C(a=Math.PI/3*i+t),180+r*S(a),150*(i?1/3:1),0,7)

Jan 4 2020 9:07 PM UTC

}// 124/140

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d/17063 #explanation

u/pavel

If you take every point on this picture, turn it into z=x+i*y and feed it through (sqrt(3)+z)/(1+sqrt(3)*z) then decode the resulting complex number as (x', y') and put a point there, you will get d/17063.
u/pavel

Of course you can't take infinitely many points so you will get a pixelated version. To get a proper version you need to solve the equation for the new, mapped, circle given the old circle so that you can use x.arc..

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pavel

function u(t) {

for(c.width=960,p=Math.PI,r=270,k=64;k--;)for(r*=k%2||C(d),n=j=k%2?7+k>>1:99;j--;x.arc(480,270,r,a=2*d*j-p/2,a))d=p/(n-1)
x.fill`evenodd`

Jun 29 2019 11:20 PM UTC

}// 137/140

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Vertex sphere

u/pavel

Based on Mathologers shirt: https://www.youtube.com/watch?v=O1sPvUr0YC0
u/KilledByAPixel

👍
u/Xen

oooooo nice
u/pavel

With more layers the middle circle does not shrink to nothing, it asymptotically approaches about 11% of the radius

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