New #crypto dweets

function u(t) {

c.width=1920 // clear the canvas
for(i=0;i<9;i++)
x.fillRect(400+i*100+S(t)*300,400,50,200) // draw 50x200 rects

} // 122/140

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    u(t) is called 60 times per second.
    t: Elapsed time in seconds.
    S: Shorthand for Math.sin.
    C: Shorthand for Math.cos.
    T: Shorthand for Math.tan.
    R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5)
    c: A 1920x1080 canvas.
    x: A 2D context for that canvas.

Try the new frontend: beta.dwitter.net
Current theme challenge: #Opposites

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KilledByAPixel

function u(t) {

for(c.width|=ﾠ=ㅤ=+[[+!+[]]+[+[]]],x.scale(ﾠ,ﾠ);ㅤ;ㅤ--)
x.fillRect(S(t)*(ﾠ+ﾠ+ﾠ)+ﾠ*ㅤ+ﾠ+ﾠ+ﾠ+ﾠ,ﾠ+ﾠ+ﾠ+ﾠ,ﾠ/(ﾠ/ﾠ+ﾠ/ﾠ),ﾠ+ﾠ)

Aug 18 2020 5:01 PM UTC

}// 114/140

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No Numbers Default with Invisible Variables

Show more comments…
u/KilledByAPixel

Uses Hangul Fillers (U+FFA0 and U+3164) for the invisible variables
u/KilledByAPixel

+[[+!+[]]+[+[]]] == 10 from jsfuck https://github.com/aemkei/jsfuck
u/KilledByAPixel

#crypto
u/joeytwiddle

Good trick!
u/Xen

niiice!
u/DataMeta

cool!!
u/sigveseb

Very nice
u/KilledByAPixel

Thank you! #default
u/katkip

#obfuscated
u/aaaaaz

damn damn damn... wonder what is the space between the two = after for(c.width| if I replace it by a normal space it kills the dweet :|
u/danny@hille.dk

+(+!+[]+[+[]]) is a slightly less verbose way to write 10, withou using any digits
u/danny@hille.dk

for(c.width|=ﾠ=ㅤ=+(+!+[]+[+[]]) ,x.scale(ﾠ,ﾠ);--ㅤ; ) x.fillRect(S(t)*(ﾠ+ﾠ+ﾠ)+ﾠ*ㅤ+ﾠ+ﾠ+ﾠ+ﾠ,ﾠ+ﾠ+ﾠ+ﾠ,ﾠ/(ﾠ/ﾠ+ﾠ/ﾠ),ﾠ+ﾠ)
u/danny@hille.dk

or less obfuscated : for(c.width|=a=i=+(+!+[]+[+[]]),x.scale(a,a);--i; ) x.fillRect(S(t)*(a+a+a)+a*i+a+a+a+a,a+a+a+a,a/(a/a+a/a),a+a)
u/andrea270872

Wow... it took me a bit to get the idea... cool trick!

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KilledByAPixel

function u(t) {

eval(unescape(escape`𭱩𭁨𚁸𚑦𫱲𚁣𛡷𪑤𭁨𯀽𪐽𨐽𝐰𜀻𪐭𛐻𩡯𫡴🐧𜱩𫠢𙰩𪐭𝐹🱦𪑬𫁒𩑣𭀨𚁱👩🀵𞐩🰶𜐵𚱩𚠹𞡩𚠹𞀫𭀥𜐪𞐸𛐱𩐴𛁱🱹𛐱𜰰𚱓𚁴𚠹𚱩𛰹𚐪𪐺𜡥𜰬𞐹𛁱🱩𚰹𞠭𜡥𜰪𤰨𪐭𭁼𜀩𚐺𩡩𫁬𥁥𮁴𚀧𧁵𡀸𜱄𧁵𡁃𜐵𙰬𨐬𮐽𨐫𤰨𭀬𩡩𫁬𤱴𮑬𩐽𙱲𩑤𙰩𚠹𞐩`.replace(/u../g,'')))

Aug 11 2020 11:05 PM UTC

}// 140/140

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Krypto the Superdog 🐕 #crypto

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taupelink

remix of d/14977 by u/taupelink

function u(t) {

t||(a=[]);c.width=72;for(i=a.length;i--;)x.fillText(String.fromCharCode(65+a[i]),i%8*9,i|7);a.lastIndexOf(r=Math.random()*26|0)+1||a.push(r)

Aug 9 2020 7:13 PM UTC

}// 140/140

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A-Z shuffle #crypto

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KilledByAPixel

function u(t) {

eval(unescape(escape`𭀿𣰽𦰮𛠮𢐮𭡡𫁵𩑝𞡣𛡯𭑴𩑲𢁔𣑌🐢🁴𩑸𭁡𬡥𨐠𨱯𫁳🐷𝀠𬡯𭱳🐲𜀠𪑤👉🡄𭱩𭁴𩑲𘐢𞰊𩡯𬠨𫠽𪐽𣰮𫁥𫡧𭁨𞱩𛐭𞰩𩡯𬠨𪠽𞐻𪠭𛐻𚑏𛡳𬁬𪑣𩐨𪐬𜀬𤱴𬡩𫡧𛡦𬡯𫑃𪁡𬡃𫱤𩐨𚁱🐸𜠳𚱓𚀫𚱮𚡮𚐪𝐵𯀰𚐭𘐨𬐭𝰸𝠦𙡱𛐸𜰷𚐩𚐊𭁨𬡯𭰠𣰮𪡯𪑮𨁠`.replace(/u../g,'')))

Aug 5 2020 8:23 PM UTC

}// 140/140

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̇̂͏̙̆̅ͭ͋͝G̥̜̀͛ͦͭ̄͑̿l̩̦̮̺̊̐̀ͫ͞i̸̬͓̪͚ͤ̇̋̕t̶̙͑ͥͬͬͫ̎ͭc̫̠͉ͭ͊ͫ̌̀͠h̨͎̖ͭ̄́ͬ̽͘ ͕͚͖͍̩͊̓͢͟D̞̩̃̀ͬͭ̀̊͝w͏̪̱̮̥̅̑ͭͨe̙ͭ̊̀̿̀̆ͪ́e̵̠ͩ̈͆̀̃ͪ̕t - Enter text to see glitched version. #crypto

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KilledByAPixel

function u(t) {

eval(unescape(escape`󠁦󠁯󠁲󠀨󠁣󠀮󠁷󠁩󠁤󠁴󠁨󠁼󠀽󠁩󠀽󠀹󠀻󠁩󠀭󠀭󠀻󠀩󠁸󠀮󠁦󠁩󠁬󠁬󠁒󠁥󠁣󠁴󠀨󠀴󠀰󠀰󠀫󠁩󠀪󠀹󠀹󠀫󠁓󠀨󠁴󠀩󠀪󠀳󠀰󠀰󠀬󠀴󠀰󠀰󠀬󠀵󠀰󠀬󠀲󠀰󠀰󠀩`.replace(/uDB40%uDC/g,'')))

Aug 4 2020 8:18 AM UTC

}// 111/140

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Secret #default #crypto

Show more comments…
u/katkip

what?
u/Irratix

..... but how does that even work
u/Xen

nicely done
u/magna

HAX!
u/KilledByAPixel

small improvement: replace DB40%uDC/ with .{8}
u/tomxor

#steganography

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DataMeta

function u(t) {

h=5381;w="test";for(i=0;i<w.length;i++)h=((h<<5)+h)+w.charCodeAt(i)
throw h

Aug 1 2020 8:46 PM UTC

}// 75/140

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simple djb-like non-#crypto hash function

u/DataMeta

1000BTC to anyone who implements SHA-2 in 140 bytes ;)

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katkip

remix of d/19573 by u/jellyedwards

function u(t) {

t||(Q=540)
r=Math.random
x.beginPath()
x.fillRect(t*200,Q,9,9)
Q-=p=S(t*S(t*S(t))-Q/99)*2
x.fillStyle=p<0?"red":"lime"

Aug 1 2020 8:52 AM UTC

}// 118/140

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#crypto graph

u/DaSpider

Any decorative reason for that r=Math.random?

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jellyedwards

function u(t) {

c.width=200
for(i=40;i--;)
x.fillText(i%2?`🐦 @Celebrity${String.fromCharCode(65+i)}`:"Send BTC h̲e̲r̲e̲ & get 2x back!",20,(i+t*t/9)*20%800)

Aug 1 2020 8:17 AM UTC

}// 140/140

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#crypto twitter hack

u/katkip

!
u/Xen

lol

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f8f82804

function u(t) {

eval(unescape(escape`䜽⡡Ɫ⤽㹢㽇⡢ⱡ╢⤺愻䰽⡡Ɫ⤽㹡⩢⽇⡡Ɫ⤻瀽⡩㴳㤪䵡瑨⹲慮摯洨⥼〩⩩⭩⬴ㄻ焽⬫椪椫椫㐱㭮㵰⩱㭥㴶㔵㌷㭦潲⡤㴱㭤⩥╌⡰ⴱⱱⴱ⤭ㄻ搫⬩㭣㴷㭦潲⠻ⴭ攻挽挪㜥温㭃㵣㭦潲⠻ⴭ搻䌽䌪挥温㭴桲潷⁃`.replace(/u(..)/g,"$1%")))

Aug 24 2018 7:30 PM UTC

}// 139/140

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RSA #crypto #compressed

u/f8f82804

G=(a,b)=>b?G(b,a%b):a;L=(a,b)=>a*b/G(a,b);p=(i=39*Math.random()|0)*i+i+41;q=++i*i+i+41;n=p*q;e=65537;for(d=1;d*e%L(p-1,q-1)-1;d++);c=7;for(;--e;c=c*7%n);C=c;for(;--d;C=C*c%n);throw C
u/f8f82804

Will throw 7 if the decryption works correctly. #slow
u/katkip

it lags so much
u/f8f82804

it should be possible to optimize the modular inversion and exponentiation, but it would probably go over the character limit

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