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function u(t) {
} //
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u(t) is called 60 times per second. t: Elapsed time in seconds. S: Shorthand for Math.sin. C: Shorthand for Math.cos. T: Shorthand for Math.tan. R: Function that generates rgba-strings, usage ex.: R(255, 255, 255, 0.5) c: A 1920x1080 canvas. x: A 2D context for that canvas.
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remix of d/20901 by u/pavel

function u(t) {

}//
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  • u/pavel
    Discovered this randomly when golfing the original. Not sure why it happens.
  • u/danny@hille.dk
    cool effect: the "feature" is caused by not truncating k=--i/120 -> k=--i/120|0 disables this feature :-)
  • u/KilledByAPixel
    👍
  • u/danny@hille.dk
    better solution: for(i=c.width|=p=g=>(g(0)?k&3:~~k/4)*200+150*g((k&1||-1)*(i%120*41/13+5*t));k=--i/120;)x.fillRect(560+p(S),240+p(C),9,9)

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function u(t) {

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function u(t) {

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  • u/Odog8
    Hmm, I' m intrested in how this works?

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function u(t) {

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  • Show more comments…
  • u/pavel
    Notice how d only takes one argument, and it ignores it.
  • u/KilledByAPixel
    I see what you did there. So many great tricks in this one.
  • u/pavel
    p+=r*=d(p+=r) the inner p+=r increments p and d ends runs with that value, however the outer p+= caches the old value of p so when d resolves the inner p+=r is silently ignored!
  • u/pavel
    #physics

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function u(t) {

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  • Infinite Triangles by MDWoolls

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function u(t) {

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  • (X=-0.7453, Y=0.1127, R=6.5e-4) section of the #mandelbrot set
  • u/pavel
    This version draws 1x3 pixels to speed up rendering. for(let i=2e3,f=(x,n=420,a=0,b=0)=>a*a+b*b<n?f(x,n-1,a*a-b*b+x,2*a*b+.1133-t/13845):n/420;i--;)x.fillRect(i,60*t,s=f(i/8e5-.7467),s) looks better in fullscreen but is 3x as slow.
  • u/pavel
    let and the automatic scoping of args in f makes this _really_ quick. I can increase the loop to 4e3 iterations and still have 60fps on my machine. Would be interesting to speed this up by rendering multiple rows per frame.
  • u/katkip
    all dweets made by u/pavel are genius
  • u/Xen
    godlike!
  • u/Qwitter
    agreed !!!!

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remix of d/16972 by u/yonatan

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  • u/ivylab
    I don't even ... this is so cool, like a forest
  • u/pavel
    This thing ((i&2)-1)*(2+i%7) takes so many characters. If somebody can figure out a shorter way to generate random-ish positive and negative numbers that aren't too close to zero that would be awesome. 7*C(i) is almost perfect but gets close to zero so you'd have trees on the path.
  • u/pavel
    Oh! 3/C(i) works well here, but has no bound which will be an issue in other contexts.
  • u/KilledByAPixel
    👍
  • u/iverjo
    Random Forest!

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function u(t) {

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  • u/pavel
    Simplified. Seems too hard to fit even into 194 chars.
  • u/pavel
    194 for(c.width|=i=36;i--;x.fillRect(-99,0,198,198))k=(i>>1)-8-t%1,b=C(A=Math.PI*(i-1/4+1/(1+1e4**k))),x.fillStyle=i%2?'#DDD':'#666',x.setTransform(a=S(A),b/2,-b,a/2,960+k*132,540-k*66-198/(1+k**4))
  • u/aleamb
    love it!
  • u/katkip
    Love it too

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function u(t) {

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